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| DATE | 2016-05-04 |
| FROM | Ruben Safir
|
| SUBJECT | Subject: [Learn] UPD Packet in an IP Datagram
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From learn-bounces-at-nylxs.com Wed May 4 14:22:44 2016
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To: "Jose A. Rodriguez" , Hangout
, learn-at-nylxs.com
From: Ruben Safir
Message-ID: <572A3DEE.2020902-at-my.liu.edu>
Date: Wed, 4 May 2016 14:22:38 -0400
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Subject: [Learn] UPD Packet in an IP Datagram
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How is a UDP Packet placed in a IP Datagram.
This relates to the question:
Assuming MTU = 1500, a 4,998,913 byte MP4 video is to be transmitted
encapsulated within UDP. Assuming standard IP header of 20 bytes and
standard UDP header of 8 bytes, how many IP datagrams are required to
transmit the entire video? Assume the payload of each UDP datagram is
such that the resulting IP datagram never exceeds the MTU and thus need
not be fragmented.
I can't find a reference to tell me how UDP is placed in IP. I have an
8 byte header in UDP. It is described in the text, but also in wikipedea
https://en.wikipedia.org/wiki/User_Datagram_Protocol#Packet_structure
But NOWHERE do I see how it is translated in the IP Datagram
Is the entire UDP packet entered in the data section?
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