MESSAGE
| DATE | 2005-01-25 |
| FROM | From: "Martin, Jared"
|
| SUBJECT | RE: [hangout] Simple C question
|
From owner-hangouts-destenys-at-mrbrklyn.com Tue Jan 25 16:36:50 2005
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Subject: RE: [hangout] Simple C question
Date: Tue, 25 Jan 2005 16:36:56 -0500
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Thread-Topic: [hangout] Simple C question
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Thanks a lot, I had seen strcpy, but strncpy is what I really needed Thanks.
Sincerely,
*****************************
Jared Martin
IT Desktop Support
Davis & Gilbert LLP
1740 Broadway
New York, NY 10019
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-----Original Message-----
From: Billy [mailto:billy-at-dadadada.net]
Sent: Tuesday, January 25, 2005 4:03 PM
To: Inker, Evan
Cc: Martin, Jared; NYLXS
Subject: Re: [hangout] Simple C question
Inker, Evan wrote:
> Check this out
>
> strcopy.c
>
> /* strcopy.c written by detour-at-metalshell.com
> *
> * example of a string copying function.
> *
> * http://www.metalshell.com/
> *
> */
>
> #include
> #include
>
> void strcopy(const char *, char *);
>
> int main() {
> char string1[] = "This is string1";
> char string2[] = "This is string2";
>
> strcopy(string1, string2);
> printf("String2: %s", string2);
> }
>
> void strcopy(const char * str1, char * str2) {
> int x = 0;
>
> /* change the size of string2 to the size of string1 */
> realloc(str2, sizeof(str1));
>
> do {
> str2[x] = str1[x];
> } while (str1[x++] != '\0');
>
> }
This program is incorrect.
YOU CANNOT overwrite the contents of string2. It is also illegal to
realloc() a pointer which was not obtained by malloc().
also, realloc is free to move the block. you have to use its return
value to update the pointer. There's just so much wrong...
I DON'T RECOMMEND learning from this example.
____________________________
NYLXS: New Yorker Free Software Users Scene
Fair Use -
because it's either fair use or useless....
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